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Page 15 of 15Section A 40 marks · 2 marks each
Write 5,326 in words.
Five thousand, three hundred twenty-six
Use =, < or > to complete: ⁻3 …… ⁺3
⁻3 < ⁺3
Negative numbers are less than positive numbers.
Shade ¼ of the diagram.
The circle has 8 equal parts. ¼ = 2⁄8, so shade 2 parts.
Convert 1,560 grammes to kilogrammes.
1,000 g = 1 kg → 1,560 ÷ 1,000
= 1.56 kg
Given ξ = {a, b, c, d, e, f, g, h}, M = {a, b, e, f} and K = {b, d}, find n(M ∪ K)′.
M ∪ K = {a, b, d, e, f}
(M ∪ K)′ = {c, g, h}
n(M ∪ K)′ = 3
Find the next number: 128, 64, 32, 16, ……
Each number is divided by 2: 16 ÷ 2
= 8
Using a protractor, draw an angle of 85°.
Draw a straight line and mark the vertex. Place the protractor’s centre on the vertex with the base line on 0°, mark the point at 85° and join it to the vertex. Label the angle 85°.
Round off 37,594 to the nearest thousands.
The hundreds digit is 5 (≥ 5), so round up.
38,000
6,625 people attended; 5,879 were adults. Find the number of children.
6,625 − 5,879
= 746 children
Work out (25 × 26) + (24 × 25).
= 25 × (26 + 24) = 25 × 50
= 1,250
Given a = ½ and b = 12, find 8a + ab.
8 × ½ + ½ × 12 = 4 + 6
= 10
Atim sold every 4 oranges for sh 1,500. Find the money from 200 oranges.
Groups of 4: 200 ÷ 4 = 50
50 × sh 1,500
= sh 75,000
Find the median of 6, 13, 7, 11, 15, 9.
Arrange: 6, 7, 9, 11, 13, 15
Median = (9 + 11) ÷ 2
= 10
Peter is twice as old as Abdul. The sum of their ages is 72 years. Find Abdul’s age.
Let Abdul = x, Peter = 2x → x + 2x = 72 → 3x = 72
x = 24 years
sh 2,000,000 borrowed; interest of sh 720,000 after 2 years. Find the rate per year.
Interest per year = 720,000 ÷ 2 = 360,000
Rate = 360,000 ÷ 2,000,000 × 100
= 18% per year
Annet visited in March 2025 and will visit again after 16 months. When?
12 months → March 2026; 4 more months → July 2026
July 2026
Find the value of k in the diagram.
The interior angle at the left vertex = 40° (vertically opposite angles).
The exterior angle 110° = sum of the two interior opposite angles: k + 40° = 110°
k = 70°
A rectangular chart is 85 cm long and 60 cm wide. Find the length of tape along the edges.
Perimeter = 2 × (85 + 60) = 2 × 145
= 290 cm
Uniform intervals: 7:30 a.m., 9:50 a.m., 12:10 p.m., ……, 4:50 p.m. Find the 4th time.
Interval = 9:50 − 7:30 = 2 hours 20 minutes
12:10 p.m. + 2 h 20 min
= 2:30 p.m.
A die is rolled once. Probability the top face shows a factor of 3.
Factors of 3 on a die: {1, 3} → 2 outcomes out of 6
P = 2⁄6 = 1⁄3
Section B 60 marks
Find n and m in the base five addition 1m2five + 224five = 40nfive. (02 marks)
Units: 2 + 4 = 6 = 1 five remainder 1 → n = 1, carry 1.
Fives: m + 2 + 1 = 5 (write 0, carry 1) → m = 2.
Check: 1 + 2 + 1 = 4 ✓
m = 2, n = 1
Write the number expanded as (6 × 10⁴) + (3 × 10²) + (5 × 10¹) + (9 × 10⁰). (02 marks)
60,000 + 300 + 50 + 9
= 60,359
Maths set sh 5,000; a dozen books sh 24,000; a pen costs half the price of a book. Cost of 8 sets, 3 books and 5 pens. (06 marks)
1 book = 24,000 ÷ 12 = sh 2,000; 1 pen = sh 1,000
8 sets = sh 40,000 · 3 books = sh 6,000 · 5 pens = sh 5,000
Total = sh 51,000
Solve 8 − 3t ≥ 23. (03 marks)
−3t ≥ 23 − 8 → −3t ≥ 15
Divide by −3 and reverse the sign:
t ≤ ⁻5
Write the solution set for ⁻2 < x < 2. (01 mark)
{⁻1, 0, 1}
800 guests each used 400 ml of water from 20-litre tanks. Find the number of full tanks used. (04 marks)
Total = 800 × 400 ml = 320,000 ml = 320 litres
Tanks = 320 ÷ 20
= 16 tanks
Represent the information (music 35, debating only 15, music only 17, b neither, 28 do not like music) on a Venn diagram. (04 marks)
Both = 35 − 17 = 18. Not music: 15 + b = 28 → b = 13.
Calculate the total number of pupils in the class. (02 marks)
17 + 18 + 15 + 13
= 63 pupils
State the bearing of the church from the mosque. (01 mark)
The line makes 30° with the west at the church, so the mosque is on 240° from the church. Back bearing: 240° − 180°
= 060°
State the bearing of the church from the hospital. (01 mark)
Hospital from church = 140°. Back bearing: 140° + 180°
= 320°
Find, in metres, the shortest distance from the hospital to the mosque (1 cm : 50 m). (02 marks)
Measure the straight line from the hospital to the mosque on the printed drawing, then multiply by 50.
e.g. 7.1 cm × 50 m
≈ 355 m
Your answer depends on your measurement of the original paper (accept close values).
Ten goats bought for sh 800,000; six sold at sh 110,000 each. Price of each remaining goat for a 25% profit. (06 marks)
Required selling price = 125% × 800,000 = sh 1,000,000
Six goats: 6 × 110,000 = sh 660,000
Remaining 4 goats: 1,000,000 − 660,000 = sh 340,000
Each goat = sh 85,000
M→K at 75 km/h for 2 h, 1 h lunch at K, then 3 h to L. Average speed 55 km/h. Find distance K to L. (05 marks)
Total time = 2 + 1 + 3 = 6 hours
Total distance = 55 × 6 = 330 km
M to K = 75 × 2 = 150 km
K to L = 330 − 150 = 180 km
A(⁻2, ⁻1), B(0, 1), C(4, 1) are vertices of parallelogram ABCD. Plot, find D and join. (05 marks)
B → C moves 4 units right, so A → D also moves 4 units right: D = (⁻2 + 4, ⁻1)
D (2, ⁻1)
Construct triangle LMN: LM = 6.5 cm, ∠NLM = 45°, ∠LMN = 60°; then a perpendicular from N to LM at K. (05 marks)
- Draw LM = 6.5 cm.
- At L, construct 90° and bisect it to get 45°.
- At M, construct 60° (equilateral arc method).
- Extend both arms to meet at N.
- (b) With centre N, cut LM at two points; from these points draw arcs below LM to meet; join N to the meeting point — it crosses LM at K (NK ⊥ LM).
Right-angled triangle RST (RS = 16 cm, ST = 12 cm, RT = 20 cm, RT a diameter) cut from a circle. Find the remaining area (π = 3.14). (06 marks)
Radius = 20 ÷ 2 = 10 cm → Circle area = 3.14 × 10 × 10 = 314 cm²
Triangle area = ½ × 16 × 12 = 96 cm²
Remaining area = 314 − 96 = 218 cm²
Janat got ⅜, Adam ⅖ and Moses ⅓ of the land. Who got the largest share? (05 marks)
LCD of 8, 5 and 3 = 120
⅜ = 45⁄120 · ⅖ = 48⁄120 · ⅓ = 40⁄120
Adam got the largest share
© Uganda National Examinations Board. Past papers are shared for revision purposes only.

